Free agency is still 30 minutes from now, but the Brooklyn Nets are already making three huge signings in an attempt to bolster their roster.
According to ESPN’s Adrian Wojnarowski, the Nets have deals in place with free agents Kyrie Irving, Kevin Durant, and DeAndre Jordan.
Brooklyn is making a clean sweep tonight: Brooklyn will sign Kevin Durant, Kyrie Irving and DeAndre Jordan, league sources tell ESPN.
— Adrian Wojnarowski (@wojespn) June 30, 2019
Irving will sign a four-year, maximum-salary contract worth roughly $141 million. The 27-year-old spent the past two seasons with the Boston Celtics after spending the first six years of his career with the Cleveland Cavaliers. The former No. 1 overall pick out of Duke has been named to six All-Star teams, including three in the past three years and six in the past seven years. Irving started all 508 games he has appeared in throughout his career, including the 67 games in the 2018-19 season with Boston. Irving averaged 23.8 PPG and a career-high 6.9 APG and 5.0 RPG with last season, but chemistry issues soured his final season in Boston.
Durant will also agree to a four-year maximum-salary deal, with his being worth $164,255,700. The 30-year-old, who was drafted second overall by the Seattle SuperSonics more than 12 years ago, spent the last three seasons with the Golden State Warriors after one with Seattle and an impressive eight-year stint with the Oklahoma City Thunder. Durant, who has been named an All-Star for 10 years in a row, has started all 849 games he has appeared in, including the 78 games he was active for last season. Durant will join Irving, a good friend of his, in Brooklyn, but the two will have to wait a little while to play together, as Durant will miss the 2019-20 season with an Achilles injury he suffered in Game 6 of the NBA Finals.
Jordan is the third of four players to finalize a deal with Brooklyn today (not mentioned yet in this article, Garrett Temple reportedly has a deal in place, too), but the terms of Jordan’s deal are not yet known. Jordan, a former Clippers 2008 second-round pick, spent the first ten years of his career in Los Angeles before splitting the 2018-19 season between Dallas with the Mavericks and New York with the Knicks. The one-time All-Star started all the games he appeared in last season, extending that streak to eight seasons. He played in 68 games last season.
